Submission #2552269


Source Code Expand

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.OutputStream;
import java.io.PrintWriter;
import java.util.InputMismatchException;
import java.util.StringTokenizer;

public class Main {

	public static void main(String[] args) throws IOException {
		InputStream inputStream = System.in;
		OutputStream outputStream = System.out;
		InputReader in = new InputReader(inputStream);
		PrintWriter out = new PrintWriter(outputStream);
		TaskX solver = new TaskX();
		solver.solve(1, in, out);
		out.close();
	}

	static int INF = 1 << 30;
	static int MOD = 1000000007;
	static int[] mh4 = { 0, -1, 1, 0 };
	static int[] mw4 = { -1, 0, 0, 1 };
	static int[] mh8 = { -1, -1, -1, 0, 0, 1, 1, 1 };
	static int[] mw8 = { -1, 0, 1, -1, 1, -1, 0, 1 };

	static class TaskX {
		public void solve(int testNumber, InputReader in, PrintWriter out) {

			int n = in.nextInt(), k = in.nextInt();
			out.println(comb(n+k-1, k));

		}
	}

	/**
	 * 二項係数
	 * 前提 n < modP
	 * nCr = n!/(r!*(n-r)!)である。この時分子分母にMODが来る場合は以下のように使用する
	 * */
	public static long comb(int n,int r) {
		return fact[n] * factInv[r] % MOD * factInv[n-r] % MOD;
	}

	/**
	 * 階乗数の逆元
	 *
	 * */
	public static int MAXN = 200000;

	static long[] fact = factorialArray(MAXN, MOD);
	static long[] factInv = factorialInverseArray(MAXN, MOD, inverseArray(MAXN, MOD));

	// 階乗の mod P テーブル
	public static long[] factorialArray(int maxN,long mod) {
		long[] fact = new long[maxN+1];
		fact[0] = 1 % mod;
		for(int i=1;i<=maxN;i++) {
			fact[i] = fact[i-1] * i % mod;
		}
		return fact;
	}
	// 数 i に対する mod P での逆元テーブル
	public static long[] inverseArray(int maxN,long modP) {
		long[] inv = new long[maxN+1];
		inv[1] = 1;
		for(int i=2;i<=maxN;i++) {
			inv[i] = modP - (modP / i) * inv[(int) (modP%i)] % modP;
		}
		return inv;
	}

	// 階乗の逆元テーブル
	public static long[] factorialInverseArray(int maxN,long modP,long[] inverseArray) {
		long[] factInv = new long[maxN+1];
		factInv[0] = 1;
		for(int i=1;i<=maxN;i++) {
			factInv[i] = factInv[i-1] * inverseArray[i] % modP;
		}
		return factInv;
	}

	static class InputReader {
		BufferedReader in;
		StringTokenizer tok;

		public String nextString() {
			while (!tok.hasMoreTokens()) {
				try {
					tok = new StringTokenizer(in.readLine(), " ");
				} catch (IOException e) {
					throw new InputMismatchException();
				}
			}
			return tok.nextToken();
		}

		public int nextInt() {
			return Integer.parseInt(nextString());
		}

		public long nextLong() {
			return Long.parseLong(nextString());
		}

		public double nextDouble() {
			return Double.parseDouble(nextString());
		}

		public int[] nextIntArray(int n) {
			int[] res = new int[n];
			for (int i = 0; i < n; i++) {
				res[i] = nextInt();
			}
			return res;
		}

		public long[] nextLongArray(int n) {
			long[] res = new long[n];
			for (int i = 0; i < n; i++) {
				res[i] = nextLong();
			}
			return res;
		}

		public InputReader(InputStream inputStream) {
			in = new BufferedReader(new InputStreamReader(inputStream));
			tok = new StringTokenizer("");
		}

	}

}

Submission Info

Submission Time
Task D - 多重ループ
User tutuz
Language Java8 (OpenJDK 1.8.0)
Score 100
Code Size 3389 Byte
Status AC
Exec Time 98 ms
Memory 27604 KB

Judge Result

Set Name Sample Subtask1 All
Score / Max Score 0 / 0 99 / 99 1 / 1
Status
AC × 5
AC × 23
AC × 33
Set Name Test Cases
Sample subtask0_sample_01.txt, subtask0_sample_02.txt, subtask0_sample_03.txt, subtask0_sample_04.txt, subtask0_sample_05.txt
Subtask1 subtask0_sample_01.txt, subtask0_sample_02.txt, subtask0_sample_03.txt, subtask0_sample_04.txt, subtask1_01.txt, subtask1_02.txt, subtask1_03.txt, subtask1_04.txt, subtask1_05.txt, subtask1_06.txt, subtask1_07.txt, subtask1_08.txt, subtask1_09.txt, subtask1_10.txt, subtask1_11.txt, subtask1_12.txt, subtask1_13.txt, subtask1_14.txt, subtask1_15.txt, subtask1_16.txt, subtask1_17.txt, subtask1_18.txt, subtask1_19.txt
All subtask0_sample_01.txt, subtask0_sample_02.txt, subtask0_sample_03.txt, subtask0_sample_04.txt, subtask0_sample_05.txt, subtask1_01.txt, subtask1_02.txt, subtask1_03.txt, subtask1_04.txt, subtask1_05.txt, subtask1_06.txt, subtask1_07.txt, subtask1_08.txt, subtask1_09.txt, subtask1_10.txt, subtask1_11.txt, subtask1_12.txt, subtask1_13.txt, subtask1_14.txt, subtask1_15.txt, subtask1_16.txt, subtask1_17.txt, subtask1_18.txt, subtask1_19.txt, subtask2_02.txt, subtask2_03.txt, subtask2_04.txt, subtask2_05.txt, subtask2_06.txt, subtask2_07.txt, subtask2_08.txt, subtask2_09.txt, subtask2_10.txt
Case Name Status Exec Time Memory
subtask0_sample_01.txt AC 97 ms 24148 KB
subtask0_sample_02.txt AC 98 ms 21204 KB
subtask0_sample_03.txt AC 96 ms 22612 KB
subtask0_sample_04.txt AC 95 ms 22228 KB
subtask0_sample_05.txt AC 96 ms 23504 KB
subtask1_01.txt AC 97 ms 22356 KB
subtask1_02.txt AC 94 ms 22100 KB
subtask1_03.txt AC 95 ms 25428 KB
subtask1_04.txt AC 96 ms 23252 KB
subtask1_05.txt AC 96 ms 23508 KB
subtask1_06.txt AC 93 ms 25428 KB
subtask1_07.txt AC 98 ms 25428 KB
subtask1_08.txt AC 96 ms 23124 KB
subtask1_09.txt AC 95 ms 24020 KB
subtask1_10.txt AC 96 ms 23380 KB
subtask1_11.txt AC 95 ms 22100 KB
subtask1_12.txt AC 94 ms 22612 KB
subtask1_13.txt AC 98 ms 23636 KB
subtask1_14.txt AC 95 ms 23636 KB
subtask1_15.txt AC 95 ms 22996 KB
subtask1_16.txt AC 95 ms 25556 KB
subtask1_17.txt AC 94 ms 21844 KB
subtask1_18.txt AC 94 ms 22100 KB
subtask1_19.txt AC 94 ms 23508 KB
subtask2_02.txt AC 96 ms 23636 KB
subtask2_03.txt AC 95 ms 22996 KB
subtask2_04.txt AC 96 ms 25044 KB
subtask2_05.txt AC 95 ms 27604 KB
subtask2_06.txt AC 94 ms 21076 KB
subtask2_07.txt AC 96 ms 22100 KB
subtask2_08.txt AC 95 ms 22228 KB
subtask2_09.txt AC 96 ms 21076 KB
subtask2_10.txt AC 95 ms 26196 KB